What are the solutions to the equation 3n^2+4n+4=0 ?

The solutions to the equation 3n^2+4n+4=0 are n=-2/3+i(2sqrt(2))/3 ,n=-2/3-i(2sqrt(2))/3

Find the zeros of 3n^2+4n+4=0

The zeros of 3n^2+4n+4=0 are n=-2/3+i(2sqrt(2))/3 ,n=-2/3-i(2sqrt(2))/3

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3 n^{2} + 4 n + 4 = 0

n = - \frac{2}{3} + i \frac{2 2}{3}, n = - \frac{2}{3} - i \frac{2 2}{3}

Solution steps

3 n^{2} + 4 n + 4 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 3 \cdot 4}{2 \cdot 3}

Simplify

4^{2} - 4 \cdot 3 \cdot 4 : 42 i

n_{1, 2} = \frac{- 4 \pm 4 2 i}{2 \cdot 3}

Separate the solutions

n_{1} = \frac{- 4 + 4 2 i}{2 \cdot 3}, n_{2} = \frac{- 4 - 4 2 i}{2 \cdot 3}

n = \frac{- 4 + 4 2 i}{2 \cdot 3} : - \frac{2}{3} + i \frac{2 2}{3}

n = \frac{- 4 - 4 2 i}{2 \cdot 3} : - \frac{2}{3} - i \frac{2 2}{3}

The solutions to the quadratic equation are:

n = - \frac{2}{3} + i \frac{2 2}{3}, n = - \frac{2}{3} - i \frac{2 2}{3}

b (c - a) x^{2} + c (a - b) x + a (b - c) = 0

a, 588 = a^{2} \cdot b

x^{2} - 1000 x - 30000 = 0

x, 12 x^{2} + 5 x y - 2 y^{2} = 0

a, \frac{b ^{2}}{c ^{2}} = \frac{1}{1} - \frac{a ^{2}}{c ^{2}}

What are the solutions to the equation 3n^2+4n+4=0 ?
The solutions to the equation 3n^2+4n+4=0 are n=-2/3+i(2sqrt(2))/3 ,n=-2/3-i(2sqrt(2))/3
Find the zeros of 3n^2+4n+4=0
The zeros of 3n^2+4n+4=0 are n=-2/3+i(2sqrt(2))/3 ,n=-2/3-i(2sqrt(2))/3