What are the solutions to the equation (x/(2-1))((3x-2)/(4-5))=0 ?

The solutions to the equation (x/(2-1))((3x-2)/(4-5))=0 are x=0,x= 2/3

Find the zeros of (x/(2-1))((3x-2)/(4-5))=0

The zeros of (x/(2-1))((3x-2)/(4-5))=0 are x=0,x= 2/3

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(\frac{x}{2 - 1}) (\frac{3 x - 2}{4 - 5}) = 0

x = 0, x = \frac{2}{3}

Decimal Notation

x = 0, x = 0.66666 \dots

Solution steps

(\frac{x}{2 - 1}) (\frac{3 x - 2}{4 - 5}) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

\frac{x}{2 - 1} = 0 or \frac{3 x - 2}{4 - 5} = 0

Solve

\frac{x}{2 - 1} = 0 : x = 0

Solve

\frac{3 x - 2}{4 - 5} = 0 : x = \frac{2}{3}

The solutions to the quadratic equation are:

x = 0, x = \frac{2}{3}

x^{2} - \frac{11}{4} x + \frac{15}{8} = 0

x, x^{2} + y^{2} + 4 y + 13 = 6 x

128.8 = 0.006 y^{2} - 0.03 y + 119

- 2 x^{2} = (5 - x) (\frac{2 x - 2}{5})

- 0.62 x^{2} + 2.8 = 0

What are the solutions to the equation (x/(2-1))((3x-2)/(4-5))=0 ?
The solutions to the equation (x/(2-1))((3x-2)/(4-5))=0 are x=0,x= 2/3
Find the zeros of (x/(2-1))((3x-2)/(4-5))=0
The zeros of (x/(2-1))((3x-2)/(4-5))=0 are x=0,x= 2/3