What are the solutions to the equation 6n^2-11n-726=0 ?

The solutions to the equation 6n^2-11n-726=0 are n=(11+11sqrt(145))/(12),n=(11-11sqrt(145))/(12)

Find the zeros of 6n^2-11n-726=0

The zeros of 6n^2-11n-726=0 are n=(11+11sqrt(145))/(12),n=(11-11sqrt(145))/(12)

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6 n^{2} - 11 n - 726 = 0

n = \frac{11 + 11 145}{12}, n = \frac{11 - 11 145}{12}

Decimal Notation

n = 11.95479 \dots, n = - 10.12146 \dots

Solution steps

6 n^{2} - 11 n - 726 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 11 ) \pm ( - 11 ) ^{2} - 4 \cdot 6 ( - 726 )}{2 \cdot 6}

(- 11)^{2} - 4 \cdot 6 (- 726) = 11145

n_{1, 2} = \frac{- ( - 11 ) \pm 11 145}{2 \cdot 6}

Separate the solutions

n_{1} = \frac{- ( - 11 ) + 11 145}{2 \cdot 6}, n_{2} = \frac{- ( - 11 ) - 11 145}{2 \cdot 6}

n = \frac{- ( - 11 ) + 11 145}{2 \cdot 6} : \frac{11 + 11 145}{12}

n = \frac{- ( - 11 ) - 11 145}{2 \cdot 6} : \frac{11 - 11 145}{12}

The solutions to the quadratic equation are:

n = \frac{11 + 11 145}{12}, n = \frac{11 - 11 145}{12}

y, y^{2} - y = x^{3} - x

x^{2} = 0.36

\frac{( x + 3 ) ( x - 1 )}{3} = \frac{( 5 x - 10 )}{2}

m, m^{2} - n^{2} = 2018

4 x^{2} - 28 x - 4 = 0

What are the solutions to the equation 6n^2-11n-726=0 ?
The solutions to the equation 6n^2-11n-726=0 are n=(11+11sqrt(145))/(12),n=(11-11sqrt(145))/(12)
Find the zeros of 6n^2-11n-726=0
The zeros of 6n^2-11n-726=0 are n=(11+11sqrt(145))/(12),n=(11-11sqrt(145))/(12)