What are the solutions to the equation 100x^2-3=20x ?

The solutions to the equation 100x^2-3=20x are x= 3/10 ,x=-1/10

Find the zeros of 100x^2-3=20x

The zeros of 100x^2-3=20x are x= 3/10 ,x=-1/10

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100 x^{2} - 3 = 20 x

x = \frac{3}{10}, x = - \frac{1}{10}

Decimal Notation

x = 0.3, x = - 0.1

Solution steps

100 x^{2} - 3 = 20 x

Move

20 x

to the left side

100 x^{2} - 3 - 20 x = 0

Write in the standard form

a x^{2} + b x + c = 0

100 x^{2} - 20 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 100 ( - 3 )}{2 \cdot 100}

(- 20)^{2} - 4 \cdot 100 (- 3) = 40

x_{1, 2} = \frac{- ( - 20 ) \pm 40}{2 \cdot 100}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 40}{2 \cdot 100}, x_{2} = \frac{- ( - 20 ) - 40}{2 \cdot 100}

x = \frac{- ( - 20 ) + 40}{2 \cdot 100} : \frac{3}{10}

x = \frac{- ( - 20 ) - 40}{2 \cdot 100} : - \frac{1}{10}

The solutions to the quadratic equation are:

x = \frac{3}{10}, x = - \frac{1}{10}

4 (x^{2} - 1) = 0

2 (a + 5) \cdot x^{2} - (a + 5) \cdot x + 1 = 0

a, (1 + a + b)^{2} = 3 (a^{2} + b^{2} + 1)

(x - 2)^{2} = (3 x + 2)^{2}

x, \frac{x ^{2}}{( a ) ^{2}} + \frac{y ^{2}}{( b ) ^{2}} = 0

What are the solutions to the equation 100x^2-3=20x ?
The solutions to the equation 100x^2-3=20x are x= 3/10 ,x=-1/10
Find the zeros of 100x^2-3=20x
The zeros of 100x^2-3=20x are x= 3/10 ,x=-1/10