What are the solutions to the equation 4x^2-24x+5=0 ?

The solutions to the equation 4x^2-24x+5=0 are x=(6+sqrt(31))/2 ,x=(6-sqrt(31))/2

Find the zeros of 4x^2-24x+5=0

The zeros of 4x^2-24x+5=0 are x=(6+sqrt(31))/2 ,x=(6-sqrt(31))/2

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4 x^{2} - 24 x + 5 = 0

x = \frac{6 + 31}{2}, x = \frac{6 - 31}{2}

Decimal Notation

x = 5.78388 \dots, x = 0.21611 \dots

Solution steps

4 x^{2} - 24 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 4 \cdot 5}{2 \cdot 4}

(- 24)^{2} - 4 \cdot 4 \cdot 5 = 431

x_{1, 2} = \frac{- ( - 24 ) \pm 4 31}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 4 31}{2 \cdot 4}, x_{2} = \frac{- ( - 24 ) - 4 31}{2 \cdot 4}

x = \frac{- ( - 24 ) + 4 31}{2 \cdot 4} : \frac{6 + 31}{2}

x = \frac{- ( - 24 ) - 4 31}{2 \cdot 4} : \frac{6 - 31}{2}

The solutions to the quadratic equation are:

x = \frac{6 + 31}{2}, x = \frac{6 - 31}{2}

x, z = 2 x y - x^{2} - 2 y^{2} + 4 y

h, 2 h^{2} + o^{2} = 2 h^{2} o

0.25 x^{2} + 0.75 x - 0.1875 = 0

a^{0.2} x (7 x + 5) - 7 x (2 x - 3) = 93

x, z = \frac{( x ^{2} + 1 )}{( 1 - 2 y )}

What are the solutions to the equation 4x^2-24x+5=0 ?
The solutions to the equation 4x^2-24x+5=0 are x=(6+sqrt(31))/2 ,x=(6-sqrt(31))/2
Find the zeros of 4x^2-24x+5=0
The zeros of 4x^2-24x+5=0 are x=(6+sqrt(31))/2 ,x=(6-sqrt(31))/2