What are the solutions to the equation 9x^2+a=a^2x+a ?

The solutions to the equation 9x^2+a=a^2x+a are x=(a^2)/9 ,x=0

Find the zeros of 9x^2+a=a^2x+a

The zeros of 9x^2+a=a^2x+a are x=(a^2)/9 ,x=0

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9 x^{2} + a = a^{2} x + a

x = \frac{a ^{2}}{9}, x = 0

Solution steps

9 x^{2} + a = a^{2} x + a

Move

a

to the left side

9 x^{2} = a^{2} x

Move

a^{2} x

to the left side

9 x^{2} - a^{2} x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - a ^{2} ) \pm ( - a ^{2} ) ^{2} - 4 \cdot 9 \cdot 0}{2 \cdot 9}

Simplify

(- a^{2})^{2} - 4 \cdot 9 \cdot 0 : a^{2}

x_{1, 2} = \frac{- ( - a ^{2} ) \pm a ^{2}}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - a ^{2} ) + a ^{2}}{2 \cdot 9}, x_{2} = \frac{- ( - a ^{2} ) - a ^{2}}{2 \cdot 9}

x = \frac{- ( - a ^{2} ) + a ^{2}}{2 \cdot 9} : \frac{a ^{2}}{9}

x = \frac{- ( - a ^{2} ) - a ^{2}}{2 \cdot 9} : 0

The solutions to the quadratic equation are:

x = \frac{a ^{2}}{9}, x = 0

2 (x - 3 x^{2}) + 5 x (x - 2) + 9 = - 8 x

x, x^{2} + y^{2} - 2 x - 4 y + k = 0

x^{2} - 3 x \cdot 2 = - 4

6 x^{2} = 14

x^{2} - 4 = \frac{5 x}{3}

What are the solutions to the equation 9x^2+a=a^2x+a ?
The solutions to the equation 9x^2+a=a^2x+a are x=(a^2)/9 ,x=0
Find the zeros of 9x^2+a=a^2x+a
The zeros of 9x^2+a=a^2x+a are x=(a^2)/9 ,x=0