What are the solutions to the equation a=x^2+16x+64 ?

The solutions to the equation a=x^2+16x+64 are x=-8+sqrt(a),x=-sqrt(a)-8

Find the zeros of a=x^2+16x+64

The zeros of a=x^2+16x+64 are x=-8+sqrt(a),x=-sqrt(a)-8

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a = x^{2} + 16 x + 64

x = - 8 + a, x = - a - 8

Solution steps

a = x^{2} + 16 x + 64

Switch sides

x^{2} + 16 x + 64 = a

Move

a

to the left side

x^{2} + 16 x + 64 - a = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot ( 64 - a )}{2 \cdot 1}

Simplify

1 6^{2} - 4 \cdot 1 \cdot (64 - a) : 2 a

x_{1, 2} = \frac{- 16 \pm 2 a}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 2 a}{2 \cdot 1}, x_{2} = \frac{- 16 - 2 a}{2 \cdot 1}

x = \frac{- 16 + 2 a}{2 \cdot 1} : - 8 + a

x = \frac{- 16 - 2 a}{2 \cdot 1} : - a - 8

The solutions to the quadratic equation are:

x = - 8 + a, x = - a - 8

a^{2} + 324 = 0

25 r^{2} + 175 r - 168 = 0

10 r^{2} - (10 + 2 (10 r - 10)) = 2.5

a (x + b)^{2} = c

b \cdot b = 288 - 98 + 200 - 162

What are the solutions to the equation a=x^2+16x+64 ?
The solutions to the equation a=x^2+16x+64 are x=-8+sqrt(a),x=-sqrt(a)-8
Find the zeros of a=x^2+16x+64
The zeros of a=x^2+16x+64 are x=-8+sqrt(a),x=-sqrt(a)-8