What are the solutions to the equation 0.2x^2-0.5x-1.2=0 ?

The solutions to the equation 0.2x^2-0.5x-1.2=0 are x=4,x=-3/2

Find the zeros of 0.2x^2-0.5x-1.2=0

The zeros of 0.2x^2-0.5x-1.2=0 are x=4,x=-3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

0.2 x^{2} - 0.5 x - 1.2 = 0

x = 4, x = - \frac{3}{2}

Decimal Notation

x = 4, x = - 1.5

Solution steps

0.2 x^{2} - 0.5 x - 1.2 = 0

Multiply both sides by

10

2 x^{2} - 5 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 12 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 12) = 11

x_{1, 2} = \frac{- ( - 5 ) \pm 11}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 11}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 11}{2 \cdot 2}

x = \frac{- ( - 5 ) + 11}{2 \cdot 2} : 4

x = \frac{- ( - 5 ) - 11}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = 4, x = - \frac{3}{2}

(n) = \frac{n ^{2}}{2} - 3 \frac{n}{2}

x^{2} - x + 1 = 0, x = 1 x = - 1

x, 2 x \cdot (6 x - 2 y^{2}) + 3 y^{2} (x - 4) = 8

x^{2} + (m - 1) x + 2 m - 6 = 0

x, x^{2} + y^{3} + 2 x - 8 y - 113 = 130

What are the solutions to the equation 0.2x^2-0.5x-1.2=0 ?
The solutions to the equation 0.2x^2-0.5x-1.2=0 are x=4,x=-3/2
Find the zeros of 0.2x^2-0.5x-1.2=0
The zeros of 0.2x^2-0.5x-1.2=0 are x=4,x=-3/2