What are the solutions to the equation 18y+5y^2=35 ?

The solutions to the equation 18y+5y^2=35 are y= 7/5 ,y=-5

Find the zeros of 18y+5y^2=35

The zeros of 18y+5y^2=35 are y= 7/5 ,y=-5

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18 y + 5 y^{2} = 35

y = \frac{7}{5}, y = - 5

Solution steps

18 y + 5 y^{2} = 35

Move

35

to the left side

18 y + 5 y^{2} - 35 = 0

Write in the standard form

a x^{2} + b x + c = 0

5 y^{2} + 18 y - 35 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 5 ( - 35 )}{2 \cdot 5}

1 8^{2} - 4 \cdot 5 (- 35) = 32

y_{1, 2} = \frac{- 18 \pm 32}{2 \cdot 5}

Separate the solutions

y_{1} = \frac{- 18 + 32}{2 \cdot 5}, y_{2} = \frac{- 18 - 32}{2 \cdot 5}

y = \frac{- 18 + 32}{2 \cdot 5} : \frac{7}{5}

y = \frac{- 18 - 32}{2 \cdot 5} : - 5

The solutions to the quadratic equation are:

y = \frac{7}{5}, y = - 5

m^{3} n - m^{2} n^{2} + 5 m n^{3}

7 - 7 x = (4 x + 9) (x - 1)

\frac{12 x y ^{7}}{6 x ^{6} y ^{5}}

- 3.28 - (- 4.4) + (- 9.7)

2 (1) + 1

What are the solutions to the equation 18y+5y^2=35 ?
The solutions to the equation 18y+5y^2=35 are y= 7/5 ,y=-5
Find the zeros of 18y+5y^2=35
The zeros of 18y+5y^2=35 are y= 7/5 ,y=-5