What are the solutions to the equation 54=(n^2-3n)/2 ?

The solutions to the equation 54=(n^2-3n)/2 are n=12,n=-9

Find the zeros of 54=(n^2-3n)/2

The zeros of 54=(n^2-3n)/2 are n=12,n=-9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

54 = \frac{n ^{2} - 3 n}{2}

n = 12, n = - 9

Solution steps

54 = \frac{n ^{2} - 3 n}{2}

Multiply both sides by

2

108 = n^{2} - 3 n

Switch sides

n^{2} - 3 n = 108

Move

108

to the left side

n^{2} - 3 n - 108 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 108 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 108) = 21

n_{1, 2} = \frac{- ( - 3 ) \pm 21}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- ( - 3 ) + 21}{2 \cdot 1}, n_{2} = \frac{- ( - 3 ) - 21}{2 \cdot 1}

n = \frac{- ( - 3 ) + 21}{2 \cdot 1} : 12

n = \frac{- ( - 3 ) - 21}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

n = 12, n = - 9

3 - 2 x + x^{2} = 0

x, a \cdot y = x^{2} + 2 (x + 1)

a = x^{2} + 16 x - 5

(y + \frac{1}{4})^{2} = \frac{9}{16}

2.5 x^{2} + 4 x + 1 = 0

What are the solutions to the equation 54=(n^2-3n)/2 ?
The solutions to the equation 54=(n^2-3n)/2 are n=12,n=-9
Find the zeros of 54=(n^2-3n)/2
The zeros of 54=(n^2-3n)/2 are n=12,n=-9