What are the solutions to the equation sqrt(3)*x^2+10x+7sqrt(3)=0 ?

The solutions to the equation sqrt(3)*x^2+10x+7sqrt(3)=0 are x=-sqrt(3),x=-7/(sqrt(3))

Find the zeros of sqrt(3)*x^2+10x+7sqrt(3)=0

The zeros of sqrt(3)*x^2+10x+7sqrt(3)=0 are x=-sqrt(3),x=-7/(sqrt(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 \cdot x^{2} + 10 x + 73 = 0

x = - 3, x = - \frac{7}{3}

Decimal Notation

x = - 1.73205 \dots, x = - 4.04145 \dots

Solution steps

3 x^{2} + 10 x + 73 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 3 \cdot 7 3}{2 3}

1 0^{2} - 43 \cdot 73 = 4

x_{1, 2} = \frac{- 10 \pm 4}{2 3}

Separate the solutions

x_{1} = \frac{- 10 + 4}{2 3}, x_{2} = \frac{- 10 - 4}{2 3}

x = \frac{- 10 + 4}{2 3} : - 3

x = \frac{- 10 - 4}{2 3} : - \frac{7}{3}

The solutions to the quadratic equation are:

x = - 3, x = - \frac{7}{3}

x, f = k^{2} x^{2} + k - 17 + 20

\frac{4 x ^{2}}{5 - 8} = 20

x^{3} + 2 x^{2} - 9 x + 18 = (x - a) (x - b) (x + c)

4 x^{2} - 4 a^{2} x + a^{4} - b^{4} = 0

6 = \frac{n ( n - 1 )}{2}

What are the solutions to the equation sqrt(3)*x^2+10x+7sqrt(3)=0 ?
The solutions to the equation sqrt(3)*x^2+10x+7sqrt(3)=0 are x=-sqrt(3),x=-7/(sqrt(3))
Find the zeros of sqrt(3)*x^2+10x+7sqrt(3)=0
The zeros of sqrt(3)*x^2+10x+7sqrt(3)=0 are x=-sqrt(3),x=-7/(sqrt(3))