en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5t^2-20t-25=0

Solution

5 t^{2} - 20 t - 25 = 0

Solution

t = 5, t = - 1

Solution steps

5 t^{2} - 20 t - 25 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 5 ( - 25 )}{2 \cdot 5}

(- 20)^{2} - 4 \cdot 5 (- 25) = 30

t_{1, 2} = \frac{- ( - 20 ) \pm 30}{2 \cdot 5}

Separate the solutions

t_{1} = \frac{- ( - 20 ) + 30}{2 \cdot 5}, t_{2} = \frac{- ( - 20 ) - 30}{2 \cdot 5}

t = \frac{- ( - 20 ) + 30}{2 \cdot 5} : 5

t = \frac{- ( - 20 ) - 30}{2 \cdot 5} : - 1

The solutions to the quadratic equation are:

t = 5, t = - 1

Popular Examples

solvefor x,f(x+h)-f=3x-4x^2 solve for

x, f (x + h) - f = 3 x - 4 x^{2}

(x^2)/3-x-9/6 = 3/2

\frac{x ^{2}}{3} - x - \frac{9}{6} = \frac{3}{2}

solvefor x,3x^2-6xy-4xy-8y^2=0 solve for

x, 3 x^{2} - 6 x y - 4 x y - 8 y^{2} = 0

solvefor x,(x-1)^2+(y+2)^4=0 solve for

x, (x - 1)^{2} + (y + 2)^{4} = 0

solvefor y,y^2(1+p^2)=r^2 solve for

y, y^{2} (1 + p^{2}) = r^{2}

Frequently Asked Questions (FAQ)

What are the solutions to the equation 5t^2-20t-25=0 ?
The solutions to the equation 5t^2-20t-25=0 are t=5,t=-1
Find the zeros of 5t^2-20t-25=0
The zeros of 5t^2-20t-25=0 are t=5,t=-1