What are the solutions to the equation solvefor x,x^2+x-p(p+1)=0 ?

The solutions to the equation solvefor x,x^2+x-p(p+1)=0 are x=p,x=-p-1

Find the zeros of solvefor x,x^2+x-p(p+1)=0

The zeros of solvefor x,x^2+x-p(p+1)=0 are x=p,x=-p-1

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solve for

x, x^{2} + x - p (p + 1) = 0

x = p, x = - p - 1

Solution steps

x^{2} + x - p (p + 1) = 0

Expand

x^{2} + x - p (p + 1) : x^{2} + x - p^{2} - p

x^{2} + x - p^{2} - p = 0

Factor

x^{2} + x - p^{2} - p : (x - p) (x + p + 1)

(x - p) (x + p + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - p = 0 or x + p + 1 = 0

Solve

x - p = 0 : x = p

Solve

x + p + 1 = 0 : x = - p - 1

The solutions to the quadratic equation are:

x = p, x = - p - 1

(7) \cdot 2 \cdot x^{2} + 7 x + 52 = 0

x, z = x y + f (x^{2} + y^{2})

h, r^{2} = h^{2} + \frac{p ^{2}}{q ^{2}}

x, f = (m - 3) x^{2} + (4 m - 8) + 3

5 x^{2} + 13 x + 30 = 0, x^{2} + 13 x

What are the solutions to the equation solvefor x,x^2+x-p(p+1)=0 ?
The solutions to the equation solvefor x,x^2+x-p(p+1)=0 are x=p,x=-p-1
Find the zeros of solvefor x,x^2+x-p(p+1)=0
The zeros of solvefor x,x^2+x-p(p+1)=0 are x=p,x=-p-1