What are the solutions to the equation ((x-3)/7)^2=4 ?

The solutions to the equation ((x-3)/7)^2=4 are x=17,x=-11

Find the zeros of ((x-3)/7)^2=4

The zeros of ((x-3)/7)^2=4 are x=17,x=-11

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(\frac{x - 3}{7})^{2} = 4

x = 17, x = - 11

Solution steps

(\frac{x - 3}{7})^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

\frac{x - 3}{7} = 4 : x = 17

Solve

\frac{x - 3}{7} = - 4 : x = - 11

The solutions to the quadratic equation are:

x = 17, x = - 11

\frac{1.5}{250} = \frac{v ^{2}}{60}

y, y^{2} \cdot (a - x) = x^{3}

1.4 z^{2} + 3.1 z = 1

\frac{x ^{2}}{4} - x + \frac{4}{10} = 8

x^{2} - 33 x + 6 = 0

What are the solutions to the equation ((x-3)/7)^2=4 ?
The solutions to the equation ((x-3)/7)^2=4 are x=17,x=-11
Find the zeros of ((x-3)/7)^2=4
The zeros of ((x-3)/7)^2=4 are x=17,x=-11