What are the solutions to the equation (((x+5))/5)*(((x-6))/7)=6 ?

The solutions to the equation (((x+5))/5)*(((x-6))/7)=6 are x=16,x=-15

Find the zeros of (((x+5))/5)*(((x-6))/7)=6

The zeros of (((x+5))/5)*(((x-6))/7)=6 are x=16,x=-15

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\frac{( x + 5 )}{5}) \cdot (\frac{( x - 6 )}{7}) = 6

x = 16, x = - 15

Solution steps

(\frac{( x + 5 )}{5}) (\frac{( x - 6 )}{7}) = 6

Expand

(\frac{x + 5}{5}) (\frac{x - 6}{7}) : \frac{x ^{2}}{35} - \frac{x}{35} - \frac{6}{7}

\frac{x ^{2}}{35} - \frac{x}{35} - \frac{6}{7} = 6

Move

6

to the left side

- \frac{48}{7} + \frac{x ^{2} - x}{35} = 0

Write in the standard form

a x^{2} + b x + c = 0

\frac{1 \cdot x ^{2}}{35} - \frac{x}{35} - \frac{48}{7} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - \frac{1}{35} ) \pm ( - \frac{1}{35} ) ^{2} - 4 \cdot \frac{1}{35} ( - \frac{48}{7} )}{2 \cdot \frac{1}{35}}

(- \frac{1}{35})^{2} - 4 \cdot \frac{1}{35} (- \frac{48}{7}) = \frac{31}{35}

x_{1, 2} = \frac{- ( - \frac{1}{35} ) \pm \frac{31}{35}}{2 \cdot \frac{1}{35}}

Separate the solutions

x_{1} = \frac{- ( - \frac{1}{35} ) + \frac{31}{35}}{2 \cdot \frac{1}{35}}, x_{2} = \frac{- ( - \frac{1}{35} ) - \frac{31}{35}}{2 \cdot \frac{1}{35}}

x = \frac{- ( - \frac{1}{35} ) + \frac{31}{35}}{2 \frac{1}{35}} : 16

x = \frac{- ( - \frac{1}{35} ) - \frac{31}{35}}{2 \frac{1}{35}} : - 15

The solutions to the quadratic equation are:

x = 16, x = - 15

a = 36 y^{2}

x^{2} = 5 - (\frac{x ^{2}}{4})

x^{2} + 2 x + c^{2} = 0

y, b = (x^{2} - 2 x y - 3) (- x \cdot y)

x, 2 y^{2} - 3 x y - 2 x^{2} + 10 x + 5 y - 12 = 0

What are the solutions to the equation (((x+5))/5)*(((x-6))/7)=6 ?
The solutions to the equation (((x+5))/5)*(((x-6))/7)=6 are x=16,x=-15
Find the zeros of (((x+5))/5)*(((x-6))/7)=6
The zeros of (((x+5))/5)*(((x-6))/7)=6 are x=16,x=-15