What are the solutions to the equation z^1+z^2-2=0 ?

The solutions to the equation z^1+z^2-2=0 are z=1,z=-2

Find the zeros of z^1+z^2-2=0

The zeros of z^1+z^2-2=0 are z=1,z=-2

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z^{1} + z^{2} - 2 = 0

z = 1, z = - 2

Solution steps

z^{1} + z^{2} - 2 = 0

Refine

z + z^{2} - 2 = 0

Write in the standard form

a x^{2} + b x + c = 0

z^{2} + z - 2 = 0

Solve with the quadratic formula

z_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 2) = 3

z_{1, 2} = \frac{- 1 \pm 3}{2 \cdot 1}

Separate the solutions

z_{1} = \frac{- 1 + 3}{2 \cdot 1}, z_{2} = \frac{- 1 - 3}{2 \cdot 1}

z = \frac{- 1 + 3}{2 \cdot 1} : 1

z = \frac{- 1 - 3}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

z = 1, z = - 2

(3) r = (x^{2} = 9 - 3 = 5)

(a - 2) \cdot x^{2} + (b - 3) x + 1 = (2 a - 8) \cdot x^{2} + (b + 5) x + 5

x, 13 x^{2} + 2 x^{2} y = 1

a, e^{2} + f^{2} = 2 (a^{2} + b^{2})

x, \frac{x ^{2}}{3} + \frac{y ^{2}}{3} = \frac{a ^{2}}{3}

What are the solutions to the equation z^1+z^2-2=0 ?
The solutions to the equation z^1+z^2-2=0 are z=1,z=-2
Find the zeros of z^1+z^2-2=0
The zeros of z^1+z^2-2=0 are z=1,z=-2