What are the solutions to the equation solvefor x,f=(2x-1)^2+3 ?

The solutions to the equation solvefor x,f=(2x-1)^2+3 are x=(sqrt(f-3)+1)/2 ,x=(-sqrt(f-3)+1)/2

Find the zeros of solvefor x,f=(2x-1)^2+3

The zeros of solvefor x,f=(2x-1)^2+3 are x=(sqrt(f-3)+1)/2 ,x=(-sqrt(f-3)+1)/2

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solve for

x, f = (2 x - 1)^{2} + 3

x = \frac{f - 3 + 1}{2}, x = \frac{- f - 3 + 1}{2}

Solution steps

f = (2 x - 1)^{2} + 3

Switch sides

(2 x - 1)^{2} + 3 = f

Move

3

to the right side

(2 x - 1)^{2} = f - 3

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

2 x - 1 = f - 3 : x = \frac{f - 3 + 1}{2}

Solve

2 x - 1 = - f - 3 : x = \frac{- f - 3 + 1}{2}

The solutions to the quadratic equation are:

x = \frac{f - 3 + 1}{2}, x = \frac{- f - 3 + 1}{2}

x, (x^{2} + c) y = 1

x^{2} + 6 c + 4 = 0

x, (b) f = 1 + x - x^{2}

a, a^{2} \cdot b^{4} \cdot c^{2} = 1

x, 4 x^{2} y^{- 1} z = 16

What are the solutions to the equation solvefor x,f=(2x-1)^2+3 ?
The solutions to the equation solvefor x,f=(2x-1)^2+3 are x=(sqrt(f-3)+1)/2 ,x=(-sqrt(f-3)+1)/2
Find the zeros of solvefor x,f=(2x-1)^2+3
The zeros of solvefor x,f=(2x-1)^2+3 are x=(sqrt(f-3)+1)/2 ,x=(-sqrt(f-3)+1)/2