What are the solutions to the equation (x^1)^2=1 ?

The solutions to the equation (x^1)^2=1 are x=1,x=-1

Find the zeros of (x^1)^2=1

The zeros of (x^1)^2=1 are x=1,x=-1

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(x^{1})^{2} = 1

x = 1, x = - 1

Solution steps

(x^{1})^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x^{1} = 1 : x = 1

Solve

x^{1} = - 1 : x = - 1

The solutions to the quadratic equation are:

x = 1, x = - 1

4 x^{2} - 4 a^{2} x + (a - b) = 0

x, p (x + 1) = x^{2} + p

a, u = 50 a - 0.5 a^{2} + 60 m - 0.25 m^{2}

(a - b) \cdot x^{2} + (b + c - a) x - c = 0

(\frac{3}{5} x - \frac{2}{3})^{2} = \frac{5}{6}

What are the solutions to the equation (x^1)^2=1 ?
The solutions to the equation (x^1)^2=1 are x=1,x=-1
Find the zeros of (x^1)^2=1
The zeros of (x^1)^2=1 are x=1,x=-1