What are the solutions to the equation solvefor x,(x+y)^2=4 ?

The solutions to the equation solvefor x,(x+y)^2=4 are x=2-y,x=-2-y

Find the zeros of solvefor x,(x+y)^2=4

The zeros of solvefor x,(x+y)^2=4 are x=2-y,x=-2-y

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solve for

x, (x + y)^{2} = 4

x = 2 - y, x = - 2 - y

Solution steps

(x + y)^{2} = 4

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + y = 4 : x = 2 - y

Solve

x + y = - 4 : x = - 2 - y

The solutions to the quadratic equation are:

x = 2 - y, x = - 2 - y

4. 5^{2} = x^{2} + 3^{2}

y^{2} - 36 \cdot 2 = 1

m, m^{2} n = 2 0^{20}

x, g = 3 x^{2} + 8 y

16716 = \frac{400 n + 4 n ^{2} + 4 n}{3}

What are the solutions to the equation solvefor x,(x+y)^2=4 ?
The solutions to the equation solvefor x,(x+y)^2=4 are x=2-y,x=-2-y
Find the zeros of solvefor x,(x+y)^2=4
The zeros of solvefor x,(x+y)^2=4 are x=2-y,x=-2-y