What are the solutions to the equation -2x^2+12x-11=0 ?

The solutions to the equation -2x^2+12x-11=0 are x=(6-sqrt(14))/2 ,x=(6+sqrt(14))/2

Find the zeros of -2x^2+12x-11=0

The zeros of -2x^2+12x-11=0 are x=(6-sqrt(14))/2 ,x=(6+sqrt(14))/2

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- 2 x^{2} + 12 x - 11 = 0

x = \frac{6 - 14}{2}, x = \frac{6 + 14}{2}

Solution steps

- 2 x^{2} + 12 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 2 ) ( - 11 )}{2 ( - 2 )}

1 2^{2} - 4 (- 2) (- 11) = 214

x_{1, 2} = \frac{- 12 \pm 2 14}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 12 + 2 14}{2 ( - 2 )}, x_{2} = \frac{- 12 - 2 14}{2 ( - 2 )}

x = \frac{- 12 + 2 14}{2 ( - 2 )} : \frac{6 - 14}{2}

x = \frac{- 12 - 2 14}{2 ( - 2 )} : \frac{6 + 14}{2}

The solutions to the quadratic equation are:

x = \frac{6 - 14}{2}, x = \frac{6 + 14}{2}

p^{2} + 9 p - 36

\frac{3 r}{5} - 1 > \frac{2}{5}

(- 4 x)^{- 3}

\frac{5 x ^{2} + 20 x y + 20 y ^{2}}{x ^{2} - x y - 6 y ^{2}}

What are the solutions to the equation -2x^2+12x-11=0 ?
The solutions to the equation -2x^2+12x-11=0 are x=(6-sqrt(14))/2 ,x=(6+sqrt(14))/2
Find the zeros of -2x^2+12x-11=0
The zeros of -2x^2+12x-11=0 are x=(6-sqrt(14))/2 ,x=(6+sqrt(14))/2