What are the solutions to the equation x^2= 4/5 x+1/5 ?

The solutions to the equation x^2= 4/5 x+1/5 are x=1,x=-1/5

Find the zeros of x^2= 4/5 x+1/5

The zeros of x^2= 4/5 x+1/5 are x=1,x=-1/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} = \frac{4}{5} x + \frac{1}{5}

x = 1, x = - \frac{1}{5}

Decimal Notation

x = 1, x = - 0.2

Solution steps

x^{2} = \frac{4}{5} x + \frac{1}{5}

Multiply both sides by

5

5 x^{2} = 4 x + 1

Move

1

to the left side

5 x^{2} - 1 = 4 x

Move

4 x

to the left side

5 x^{2} - 1 - 4 x = 0

Write in the standard form

a x^{2} + b x + c = 0

5 x^{2} - 4 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 5 ( - 1 )}{2 \cdot 5}

(- 4)^{2} - 4 \cdot 5 (- 1) = 6

x_{1, 2} = \frac{- ( - 4 ) \pm 6}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 6}{2 \cdot 5}, x_{2} = \frac{- ( - 4 ) - 6}{2 \cdot 5}

x = \frac{- ( - 4 ) + 6}{2 \cdot 5} : 1

x = \frac{- ( - 4 ) - 6}{2 \cdot 5} : - \frac{1}{5}

The solutions to the quadratic equation are:

x = 1, x = - \frac{1}{5}

x, f (a + 1) = (x)^{2} - 3 (x) - 4

a, 4 a^{2} - 16 b^{2} = (2 a - 4 b) 2

x, f x = - 14 x^{2} + 185 x + 360

p, p^{2} + q^{2} = z

- (\frac{a}{2})^{2} + 3 (- \frac{a}{2}) + 1 = 0

What are the solutions to the equation x^2= 4/5 x+1/5 ?
The solutions to the equation x^2= 4/5 x+1/5 are x=1,x=-1/5
Find the zeros of x^2= 4/5 x+1/5
The zeros of x^2= 4/5 x+1/5 are x=1,x=-1/5