What are the solutions to the equation solvefor x,6x^2-11xy+3y^2=0 ?

The solutions to the equation solvefor x,6x^2-11xy+3y^2=0 are x=(3y)/2 ,x= y/3

Find the zeros of solvefor x,6x^2-11xy+3y^2=0

The zeros of solvefor x,6x^2-11xy+3y^2=0 are x=(3y)/2 ,x= y/3

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solve for

x, 6 x^{2} - 11 x y + 3 y^{2} = 0

x = \frac{3 y}{2}, x = \frac{y}{3}

Solution steps

6 x^{2} - 11 x y + 3 y^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

6 x^{2} - 11 y x + 3 y^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 11 y ) \pm ( - 11 y ) ^{2} - 4 \cdot 6 \cdot 3 y ^{2}}{2 \cdot 6}

Simplify

(- 11 y)^{2} - 4 \cdot 6 \cdot 3 y^{2} : 7 y

x_{1, 2} = \frac{- ( - 11 y ) \pm 7 y}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 11 y ) + 7 y}{2 \cdot 6}, x_{2} = \frac{- ( - 11 y ) - 7 y}{2 \cdot 6}

x = \frac{- ( - 11 y ) + 7 y}{2 \cdot 6} : \frac{3 y}{2}

x = \frac{- ( - 11 y ) - 7 y}{2 \cdot 6} : \frac{y}{3}

The solutions to the quadratic equation are:

x = \frac{3 y}{2}, x = \frac{y}{3}

- 5 x \cdot (1 + 3 x) = \frac{3 ( x - 3 ) - ( 2 x - 10 )}{2}

c = (x^{2} + x) 2 + 9 x^{2} + 9 x + 14

6 a^{3} + 5 x^{2} - 7 x = 6

x, f (x^{2}) = 1 - x^{2}

9 y^{2} - 3 y - 2 = 0

What are the solutions to the equation solvefor x,6x^2-11xy+3y^2=0 ?
The solutions to the equation solvefor x,6x^2-11xy+3y^2=0 are x=(3y)/2 ,x= y/3
Find the zeros of solvefor x,6x^2-11xy+3y^2=0
The zeros of solvefor x,6x^2-11xy+3y^2=0 are x=(3y)/2 ,x= y/3