What are the solutions to the equation solvefor x,6x^2-xy-12y^2-8x+29y-14=0 ?

The solutions to the equation solvefor x,6x^2-xy-12y^2-8x+29y-14=0 are x=(3y-2)/2 ,x=(-4y+7)/3

Find the zeros of solvefor x,6x^2-xy-12y^2-8x+29y-14=0

The zeros of solvefor x,6x^2-xy-12y^2-8x+29y-14=0 are x=(3y-2)/2 ,x=(-4y+7)/3

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solve for

x, 6 x^{2} - x y - 12 y^{2} - 8 x + 29 y - 14 = 0

x = \frac{3 y - 2}{2}, x = \frac{- 4 y + 7}{3}

Solution steps

6 x^{2} - x y - 12 y^{2} - 8 x + 29 y - 14 = 0

Write in the standard form

a x^{2} + b x + c = 0

6 x^{2} - (y + 8) x - 12 y^{2} + 29 y - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - y - 8 ) \pm ( - y - 8 ) ^{2} - 4 \cdot 6 ( - 12 y ^{2} + 29 y - 14 )}{2 \cdot 6}

Simplify

(- y - 8)^{2} - 4 \cdot 6 (- 12 y^{2} + 29 y - 14) : 17 y - 20

x_{1, 2} = \frac{- ( - y - 8 ) \pm ( 17 y - 20 )}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - y - 8 ) + 17 y - 20}{2 \cdot 6}, x_{2} = \frac{- ( - y - 8 ) - ( 17 y - 20 )}{2 \cdot 6}

x = \frac{- ( - y - 8 ) + 17 y - 20}{2 \cdot 6} : \frac{3 y - 2}{2}

x = \frac{- ( - y - 8 ) - ( 17 y - 20 )}{2 \cdot 6} : \frac{- 4 y + 7}{3}

The solutions to the quadratic equation are:

x = \frac{3 y - 2}{2}, x = \frac{- 4 y + 7}{3}

x^{2} + 3 = 311

x, x^{2} - x y + 4 y = 3

x, 2 x^{2} - x y + 7 x + 2 y - y^{2} - 7 = 0

\frac{5}{2} x^{2} + \frac{2}{5} = 1 - 2 x

x, f (x + 1) = 3 x^{2} + 4 x - 3

What are the solutions to the equation solvefor x,6x^2-xy-12y^2-8x+29y-14=0 ?
The solutions to the equation solvefor x,6x^2-xy-12y^2-8x+29y-14=0 are x=(3y-2)/2 ,x=(-4y+7)/3
Find the zeros of solvefor x,6x^2-xy-12y^2-8x+29y-14=0
The zeros of solvefor x,6x^2-xy-12y^2-8x+29y-14=0 are x=(3y-2)/2 ,x=(-4y+7)/3