What are the solutions to the equation x^1+2x^2=5 ?

The solutions to the equation x^1+2x^2=5 are x=(-1+sqrt(41))/4 ,x=(-1-sqrt(41))/4

Find the zeros of x^1+2x^2=5

The zeros of x^1+2x^2=5 are x=(-1+sqrt(41))/4 ,x=(-1-sqrt(41))/4

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x^{1} + 2 x^{2} = 5

x = \frac{- 1 + 41}{4}, x = \frac{- 1 - 41}{4}

Decimal Notation

x = 1.35078 \dots, x = - 1.85078 \dots

Solution steps

x^{1} + 2 x^{2} = 5

Refine

x + 2 x^{2} = 5

Move

5

to the left side

x + 2 x^{2} - 5 = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} + x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 5 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 5) = 41

x_{1, 2} = \frac{- 1 \pm 41}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 1 + 41}{2 \cdot 2}, x_{2} = \frac{- 1 - 41}{2 \cdot 2}

x = \frac{- 1 + 41}{2 \cdot 2} : \frac{- 1 + 41}{4}

x = \frac{- 1 - 41}{2 \cdot 2} : \frac{- 1 - 41}{4}

The solutions to the quadratic equation are:

x = \frac{- 1 + 41}{4}, x = \frac{- 1 - 41}{4}

x (4 - x) + 5 x = x^{2} + 3 x

6 x^{2} - 29 x + 35 = 0

14.6689 = x^{2} + x

(x - 2)^{3} - x^{3} + 6 x + 7 = 0

x, x^{2} + y^{2} + z^{2} - 2 x + 4 y + 5 = 0

What are the solutions to the equation x^1+2x^2=5 ?
The solutions to the equation x^1+2x^2=5 are x=(-1+sqrt(41))/4 ,x=(-1-sqrt(41))/4
Find the zeros of x^1+2x^2=5
The zeros of x^1+2x^2=5 are x=(-1+sqrt(41))/4 ,x=(-1-sqrt(41))/4