What are the solutions to the equation x^2-(7+sqrt(3))*x+6(1+sqrt(3))=0 ?

The solutions to the equation x^2-(7+sqrt(3))*x+6(1+sqrt(3))=0 are x=6,x=1+sqrt(3)

Find the zeros of x^2-(7+sqrt(3))*x+6(1+sqrt(3))=0

The zeros of x^2-(7+sqrt(3))*x+6(1+sqrt(3))=0 are x=6,x=1+sqrt(3)

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x^{2} - (7 + 3) \cdot x + 6 (1 + 3) = 0

x = 6, x = 1 + 3

Decimal Notation

x = 6, x = 2.73205 \dots

Solution steps

x^{2} - (7 + 3) x + 6 (1 + 3) = 0

Expand

x^{2} - (7 + 3) x + 6 (1 + 3) : x^{2} - 7 x - 3 x + 6 + 63

x^{2} - 7 x - 3 x + 6 + 63 = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - (7 + 3) x + 6 + 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 - 3 ) \pm ( - 7 - 3 ) ^{2} - 4 \cdot 1 \cdot ( 6 + 6 3 )}{2 \cdot 1}

(- 7 - 3)^{2} - 4 \cdot 1 \cdot (6 + 63) = 5 - 3

x_{1, 2} = \frac{- ( - 7 - 3 ) \pm ( 5 - 3 )}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 - 3 ) + 5 - 3}{2 \cdot 1}, x_{2} = \frac{- ( - 7 - 3 ) - ( 5 - 3 )}{2 \cdot 1}

x = \frac{- ( - 7 - 3 ) + 5 - 3}{2 \cdot 1} : 6

x = \frac{- ( - 7 - 3 ) - ( 5 - 3 )}{2 \cdot 1} : 1 + 3

The solutions to the quadratic equation are:

x = 6, x = 1 + 3

a, (1 - m)^{2} (m^{2} + a^{2}) = 0

x^{2} + (m + n) \cdot x - 2 (m - n) = 0

a (x) = \frac{3}{16} x^{2} - 18 x + 670

x, x^{2} + 4 y^{2} + 9 z^{2} - 2 x - 4 y - 6 z + 3 = 0

x, x^{2} + y^{2} - 113 = x^{2} y^{3}

What are the solutions to the equation x^2-(7+sqrt(3))*x+6(1+sqrt(3))=0 ?
The solutions to the equation x^2-(7+sqrt(3))*x+6(1+sqrt(3))=0 are x=6,x=1+sqrt(3)
Find the zeros of x^2-(7+sqrt(3))*x+6(1+sqrt(3))=0
The zeros of x^2-(7+sqrt(3))*x+6(1+sqrt(3))=0 are x=6,x=1+sqrt(3)