What are the solutions to the equation solvefor x,x^2-y=y^2-x ?

The solutions to the equation solvefor x,x^2-y=y^2-x are x=y,x=-y-1

Find the zeros of solvefor x,x^2-y=y^2-x

The zeros of solvefor x,x^2-y=y^2-x are x=y,x=-y-1

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solve for

x, x^{2} - y = y^{2} - x

x = y, x = - y - 1

Solution steps

x^{2} - y = y^{2} - x

Move

x

to the left side

x^{2} - y + x = y^{2}

Move

y^{2}

to the left side

x^{2} - y + x - y^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + x - y - y^{2} = 0

Factor

x^{2} + x - y - y^{2} : (x - y) (x + y + 1)

(x - y) (x + y + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - y = 0 or x + y + 1 = 0

Solve

x - y = 0 : x = y

Solve

x + y + 1 = 0 : x = - y - 1

The solutions to the quadratic equation are:

x = y, x = - y - 1

21 x^{2} + 21 x - 254 = 0

t^{2} + 3 t - 6 = 0

x, x + y + z = f (x^{2} + y^{2} + z^{2})

a, a^{3} + b^{3} = (a + b)^{3}

\frac{4}{8} x^{2} + \frac{3}{2} x - 0.5 = 0

What are the solutions to the equation solvefor x,x^2-y=y^2-x ?
The solutions to the equation solvefor x,x^2-y=y^2-x are x=y,x=-y-1
Find the zeros of solvefor x,x^2-y=y^2-x
The zeros of solvefor x,x^2-y=y^2-x are x=y,x=-y-1