What are the solutions to the equation (3x)^2-2=1 ?

The solutions to the equation (3x)^2-2=1 are x= 1/(sqrt(3)),x=-1/(sqrt(3))

Find the zeros of (3x)^2-2=1

The zeros of (3x)^2-2=1 are x= 1/(sqrt(3)),x=-1/(sqrt(3))

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(3 x)^{2} - 2 = 1

x = \frac{1}{3}, x = - \frac{1}{3}

Decimal Notation

x = 0.57735 \dots, x = - 0.57735 \dots

Solution steps

(3 x)^{2} - 2 = 1

Expand

(3 x)^{2} - 2 : 9 x^{2} - 2

9 x^{2} - 2 = 1

Move

2

to the right side

9 x^{2} = 3

Divide both sides by

9

x^{2} = \frac{1}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{3}, x = - \frac{1}{3}

\frac{1}{3} = \frac{1}{3}

- \frac{1}{3} = - \frac{1}{3}

x = \frac{1}{3}, x = - \frac{1}{3}

x, \frac{( x ^{2} + m ^{2} )}{v} = \frac{( v ^{2} - s )}{m}

x, x^{2} + y^{2} + z^{2} = x + y + z + 84

x, [3 p + 1] \cdot x^{2} + 2 [p + 1] \cdot x + p = 0

\frac{m}{n} \cdot x^{2} + \frac{n}{m} = 1 - 2 x

e = d^{2} \cdot 10 + d^{1}

What are the solutions to the equation (3x)^2-2=1 ?
The solutions to the equation (3x)^2-2=1 are x= 1/(sqrt(3)),x=-1/(sqrt(3))
Find the zeros of (3x)^2-2=1
The zeros of (3x)^2-2=1 are x= 1/(sqrt(3)),x=-1/(sqrt(3))