What is the answer to 2^{x^2-4}=3^{x^2-4} ?

The answer to 2^{x^2-4}=3^{x^2-4} is x=-2,x=2

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2^{x^2-4}=3^{x^2-4}

2^{x^{2} - 4} = 3^{x^{2} - 4}

x = - 2, x = 2

Solution steps

2^{x^{2} - 4} = 3^{x^{2} - 4}

Apply exponent rules

(x^{2} - 4) ln (2) = (x^{2} - 4) ln (3)

Solve

(x^{2} - 4) ln (2) = (x^{2} - 4) ln (3) : x = - 2, x = 2

x = - 2, x = 2

9^{x} + 3 3^{x} = 12 1^{x}

\frac{2 ^{x - 1} + 1}{( 2 ^{x - 3} )} = 5

2^{x} = 3^{x}

8 (3^{x}) + 5 (2^{x}) - 6^{x} = 40

2^{x} = x^{2}

What is the answer to 2^{x^2-4}=3^{x^2-4} ?
The answer to 2^{x^2-4}=3^{x^2-4} is x=-2,x=2
Solve for x: 2^{x^2-4}=3^{x^2-4}
The solution is x=-2,x=2