What is the answer to solvefor x,3^x+3^y=10 ?

The answer to solvefor x,3^x+3^y=10 is x=(ln(10-3^y))/(ln(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,3^x+3^y=10

solve for

x, 3^{x} + 3^{y} = 10

x = \frac{ln ( 10 - 3 ^{y} )}{ln ( 3 )}

Solution steps

3^{x} + 3^{y} = 10

Move

3^{y}

to the right side

3^{x} = 10 - 3^{y}

Apply exponent rules

x ln (3) = ln (10 - 3^{y})

Solve

x ln (3) = ln (10 - 3^{y}) : x = \frac{ln ( 10 - 3 ^{y} )}{ln ( 3 )}

x = \frac{ln ( 10 - 3 ^{y} )}{ln ( 3 )}

2^{x} = 5

2^{x} = 1

2^{x} = 0

3^{x} + 3^{- x} = 3

(2^{3})^{x} = 6

What is the answer to solvefor x,3^x+3^y=10 ?
The answer to solvefor x,3^x+3^y=10 is x=(ln(10-3^y))/(ln(3))