What is the answer to 3^x=2 ?

The answer to 3^x=2 is x=(ln(2))/(ln(3))

The solution is x=(ln(2))/(ln(3))

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3^x=2

3^{x} = 2

x = \frac{ln ( 2 )}{ln ( 3 )}

Decimal Notation

x = 0.63092 \dots

Solution steps

3^{x} = 2

Apply exponent rules

x ln (3) = ln (2)

Solve

x ln (3) = ln (2) : x = \frac{ln ( 2 )}{ln ( 3 )}

x = \frac{ln ( 2 )}{ln ( 3 )}

x^{l o g_{10} (x)} = 10

(3 + 22)^{\frac{x}{2}} + (3 - 22)^{\frac{x}{2}} - 34 = 0

2^{x} = - 2

3^{x + 1} = 9

3^{x + 3} - 3^{x + 2} = 2