What is the answer to |2^x-1|+|2^x+1|=2 ?

The answer to |2^x-1|+|2^x+1|=2 is x<= 0

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|2^x-1|+|2^x+1|=2

∣ 2^{x} - 1 ∣ + ∣ 2^{x} + 1 ∣ = 2

x \leq 0

Solution steps

∣ 2^{x} - 1 ∣ + ∣ 2^{x} + 1 ∣ = 2

Rewrite the equation with

2^{x} = u

∣ u - 1 ∣ + ∣ u + 1 ∣ = 2

Solve

∣ u - 1 ∣ + ∣ u + 1 ∣ = 2 : - 1 \leq u \leq 1

- 1 \leq u \leq 1

Substitute back

2^{x} = u,

solve for

x

Solve

- 1 \leq 2^{x} \leq 1 : x \leq 0

x \leq 0

x, \frac{1 0 ^{x}}{1 0 ^{y}} = 100

x = 2^{x}

4^{x} = 16

2^{x} = \frac{1}{8}

(\frac{1}{3})^{2 x - 1} = 9

What is the answer to |2^x-1|+|2^x+1|=2 ?
The answer to |2^x-1|+|2^x+1|=2 is x<= 0
Solve for x: |2^x-1|+|2^x+1|=2
The solution is x<= 0