What is the answer to 2^{x+1}=3^x ?

The answer to 2^{x+1}=3^x is x=(ln(2))/(ln(3)-ln(2))

Solve for x: 2^{x+1}=3^x

The solution is x=(ln(2))/(ln(3)-ln(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2^{x + 1} = 3^{x}

x = \frac{ln ( 2 )}{ln ( 3 ) - ln ( 2 )}

Decimal Notation

x = 1.70951 \dots

Solution steps

2^{x + 1} = 3^{x}

Apply exponent rules

(x + 1) ln (2) = x ln (3)

Solve

(x + 1) ln (2) = x ln (3) : x = \frac{ln ( 2 )}{ln ( 3 ) - ln ( 2 )}

x = \frac{ln ( 2 )}{ln ( 3 ) - ln ( 2 )}

(\frac{4}{3})^{x} \cdot (\frac{3}{8})^{x} = 2

e^{x} = - 1

m, 2^{m} - 2^{n} = 2016

2^{x + 1} + 4^{x} = 8

2^{x} = 8

What is the answer to 2^{x+1}=3^x ?
The answer to 2^{x+1}=3^x is x=(ln(2))/(ln(3)-ln(2))
Solve for x: 2^{x+1}=3^x
The solution is x=(ln(2))/(ln(3)-ln(2))