What are the solutions to the equation x^2+18x+4=0 ?

The solutions to the equation x^2+18x+4=0 are x=-9+sqrt(77),x=-9-sqrt(77)

Find the zeros of x^2+18x+4=0

The zeros of x^2+18x+4=0 are x=-9+sqrt(77),x=-9-sqrt(77)

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x^{2} + 18 x + 4 = 0

x = - 9 + 77, x = - 9 - 77

Decimal Notation

x = - 0.22503 \dots, x = - 17.77496 \dots

Solution steps

x^{2} + 18 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot 4 = 277

x_{1, 2} = \frac{- 18 \pm 2 77}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 18 + 2 77}{2 \cdot 1}, x_{2} = \frac{- 18 - 2 77}{2 \cdot 1}

x = \frac{- 18 + 2 77}{2 \cdot 1} : - 9 + 77

x = \frac{- 18 - 2 77}{2 \cdot 1} : - 9 - 77

The solutions to the quadratic equation are:

x = - 9 + 77, x = - 9 - 77

cos^{2} (x) - sin^{2} (x)

\frac{m ^{\frac{3}{2}}}{4 m ^{\frac{3}{2}}}

2^{18}

4 w - 7 = 6 w + 31

2 (4 x - 4) = - 20 - 4 x

What are the solutions to the equation x^2+18x+4=0 ?
The solutions to the equation x^2+18x+4=0 are x=-9+sqrt(77),x=-9-sqrt(77)
Find the zeros of x^2+18x+4=0
The zeros of x^2+18x+4=0 are x=-9+sqrt(77),x=-9-sqrt(77)