What is the answer to solvefor x,3^x+1/3 y= 10/3 ?

The answer to solvefor x,3^x+1/3 y= 10/3 is x=(ln(10/3-1/3 y))/(ln(3))

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solvefor x,3^x+1/3 y= 10/3

solve for

x, 3^{x} + \frac{1}{3} y = \frac{10}{3}

x = \frac{ln ( \frac{10}{3} - \frac{1}{3} y )}{ln ( 3 )}

Solution steps

3^{x} + \frac{1}{3} y = \frac{10}{3}

Move

\frac{1}{3} y

to the right side

3^{x} = \frac{10}{3} - \frac{1}{3} y

Apply exponent rules

x ln (3) = ln (\frac{10}{3} - \frac{1}{3} y)

Solve

x ln (3) = ln (\frac{10}{3} - \frac{1}{3} y) : x = \frac{ln ( \frac{10}{3} - \frac{1}{3} y )}{ln ( 3 )}

x = \frac{ln ( \frac{10}{3} - \frac{1}{3} y )}{ln ( 3 )}

16 = \frac{( 2 ^{3 n + 1} + 2 ^{n + 2} )}{( 2 + 4 ^{n} )}

5^{n + 1} + 5^{2 - n} = 5^{3} + 1

e^{2} x - 6 e^{x} + 5 = 0

4^{- x} = (2^{- x})^{2}

2 5^{n - 1} + 100 = 5^{2 n - 1}

What is the answer to solvefor x,3^x+1/3 y= 10/3 ?
The answer to solvefor x,3^x+1/3 y= 10/3 is x=(ln(10/3-1/3 y))/(ln(3))