What is the answer to 2^{x+2}-2^x=4 ?

The answer to 2^{x+2}-2^x=4 is x=(ln(4/3))/(ln(2))

Solve for x: 2^{x+2}-2^x=4

The solution is x=(ln(4/3))/(ln(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2^{x + 2} - 2^{x} = 4

x = \frac{ln ( \frac{4}{3} )}{ln ( 2 )}

Decimal Notation

x = 0.41503 \dots

Solution steps

2^{x + 2} - 2^{x} = 4

Factor

2^{x + 2} - 2^{x} : 3 \cdot 2^{x}

3 \cdot 2^{x} = 4

Divide both sides by

3

2^{x} = \frac{4}{3}

Apply exponent rules

x ln (2) = ln (\frac{4}{3})

Solve

x ln (2) = ln (\frac{4}{3}) : x = \frac{ln ( \frac{4}{3} )}{ln ( 2 )}

x = \frac{ln ( \frac{4}{3} )}{ln ( 2 )}

4 9^{x + 1} + 7^{2 x} = 350

x, 2^{x} = 3^{y}

e^{x - 1} = x^{e - 1}

(\frac{2}{3})^{x} = \frac{9}{4}

3^{x} + 3^{- x} = \frac{10}{3}

What is the answer to 2^{x+2}-2^x=4 ?
The answer to 2^{x+2}-2^x=4 is x=(ln(4/3))/(ln(2))
Solve for x: 2^{x+2}-2^x=4
The solution is x=(ln(4/3))/(ln(2))