What is the answer to 6^{x+1}=2^x ?

The answer to 6^{x+1}=2^x is x=-(ln(6))/(ln(3))

Solve for x: 6^{x+1}=2^x

The solution is x=-(ln(6))/(ln(3))

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6^{x + 1} = 2^{x}

x = - \frac{ln ( 6 )}{ln ( 3 )}

Decimal Notation

x = - 1.63092 \dots

Solution steps

6^{x + 1} = 2^{x}

Apply exponent rules

(x + 1) ln (6) = x ln (2)

Solve

(x + 1) ln (6) = x ln (2) : x = - \frac{ln ( 6 )}{ln ( 3 )}

x = - \frac{ln ( 6 )}{ln ( 3 )}

7^{x^{2} - 13 x + 45} = 16807

1. 2^{x} = 10

59 = 1 1^{x}

(\frac{1}{16})^{n} = 4

e^{y} = - 3

What is the answer to 6^{x+1}=2^x ?
The answer to 6^{x+1}=2^x is x=-(ln(6))/(ln(3))
Solve for x: 6^{x+1}=2^x
The solution is x=-(ln(6))/(ln(3))