What is the answer to 3^x+3+3^x-27=2241 ?

The answer to 3^x+3+3^x-27=2241 is x=(ln(2265/2))/(ln(3))

Solve for x: 3^x+3+3^x-27=2241

The solution is x=(ln(2265/2))/(ln(3))

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3^{x} + 3 + 3^{x} - 27 = 2241

x = \frac{ln ( \frac{2265}{2} )}{ln ( 3 )}

Decimal Notation

x = 6.40096 \dots

Solution steps

3^{x} + 3 + 3^{x} - 27 = 2241

Group like terms

3^{x} + 3^{x} + 3 - 27 = 2241

Add similar elements:

3^{x} + 3^{x} = 2 \cdot 3^{x}

2 \cdot 3^{x} + 3 - 27 = 2241

Add/Subtract the numbers:

3 - 27 = - 24

2 \cdot 3^{x} - 24 = 2241

Move

24

to the right side

2 \cdot 3^{x} = 2265

Divide both sides by

2

3^{x} = \frac{2265}{2}

Apply exponent rules

x ln (3) = ln (\frac{2265}{2})

Solve

x ln (3) = ln (\frac{2265}{2}) : x = \frac{ln ( \frac{2265}{2} )}{ln ( 3 )}

x = \frac{ln ( \frac{2265}{2} )}{ln ( 3 )}

1 0^{x} = 2

7^{2 x} - 7^{x + 1} - 8 = 0

3 \cdot 8 1^{x} = 9^{x + 4}

k, (y^{k})^{- 2} = y^{5}

1.4 = (\frac{3}{100})^{t}

What is the answer to 3^x+3+3^x-27=2241 ?
The answer to 3^x+3+3^x-27=2241 is x=(ln(2265/2))/(ln(3))
Solve for x: 3^x+3+3^x-27=2241
The solution is x=(ln(2265/2))/(ln(3))