What is the answer to 2^{(x+2)(x^2-5x+6)}=1 ?

The answer to 2^{(x+2)(x^2-5x+6)}=1 is x=-2,x=2,x=3

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2^{(x+2)(x^2-5x+6)}=1

2^{(x + 2) (x^{2} - 5 x + 6)} = 1

x = - 2, x = 2, x = 3

Solution steps

2^{(x + 2) (x^{2} - 5 x + 6)} = 1

Apply exponent rules

(x + 2) (x^{2} - 5 x + 6) ln (2) = ln (1)

Solve

(x + 2) (x^{2} - 5 x + 6) ln (2) = ln (1) : x = - 2, x = 2, x = 3

x = - 2, x = 2, x = 3

16 (2.9)^{x} = (6.4)^{x}

5^{x} = \frac{1}{125}

n, a = p (1 + i)^{n}

3^{2 y + 1} = 7^{y}

\frac{( 2 ^{x} + 1 )}{( 2 ^{x} - 1 )} = 5

What is the answer to 2^{(x+2)(x^2-5x+6)}=1 ?
The answer to 2^{(x+2)(x^2-5x+6)}=1 is x=-2,x=2,x=3
Solve for x: 2^{(x+2)(x^2-5x+6)}=1
The solution is x=-2,x=2,x=3