What is the answer to (sqrt(3^x)+3)/((sqrt(3^x)))=4 ?

The answer to (sqrt(3^x)+3)/((sqrt(3^x)))=4 is x=0

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(sqrt(3^x)+3)/((sqrt(3^x)))=4

\frac{3 ^{x} + 3}{( 3 ^{x} )} = 4

x = 0

Solution steps

\frac{3 ^{x} + 3}{( 3 ^{x} )} = 4

Multiply both sides by

3^{x}

\frac{3 ^{x} + 3}{3 ^{x}} 3^{x} = 4 3^{x}

Simplify

3^{x} + 3 = 4 3^{x}

Rewrite the equation with

3^{x} = u

u + 3 = 4 u

Solve

u + 3 = 4 u : u = 1

u = 1

Substitute back

u = 3^{x},

solve for

x

Solve

3^{x} = 1 : x = 0

x = 0

Verify Solutions:

x = 0

True

The solution is

x = 0

e^{z} = 0

0. 1^{n} = 0.1333

e^{x} = e^{2}

\frac{1}{( 2 ^{x - 4} )} - \frac{1}{( 2 ^{x - 2} )} = 3

n, z^{n} = - 1

What is the answer to (sqrt(3^x)+3)/((sqrt(3^x)))=4 ?
The answer to (sqrt(3^x)+3)/((sqrt(3^x)))=4 is x=0
Solve for x: (sqrt(3^x)+3)/((sqrt(3^x)))=4
The solution is x=0