What is the answer to (2^{5x})/((2^{x+2))}=1 ?

The answer to (2^{5x})/((2^{x+2))}=1 is x= 1/2

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(2^{5x})/((2^{x+2))}=1

\frac{2 ^{5 x}}{( 2 ^{x + 2} )} = 1

x = \frac{1}{2}

Decimal Notation

x = 0.5

Solution steps

\frac{2 ^{5 x}}{( 2 ^{x + 2} )} = 1

Apply exponent rules

(4 x - 2) ln (2) = ln (1)

Solve

(4 x - 2) ln (2) = ln (1) : x = \frac{1}{2}

x = \frac{1}{2}

Verify Solutions:

x = \frac{1}{2}

True

The solution is

x = \frac{1}{2}

a, (x) = x^{2} \cdot e^{a - x^{3}}

777 = 34 3^{x}

x^{x + 1} = x^{2 - x}

3^{2 x + 1} = 2^{x - 2}

2 7^{x} = \frac{9}{( 3 ^{x} )}

What is the answer to (2^{5x})/((2^{x+2))}=1 ?
The answer to (2^{5x})/((2^{x+2))}=1 is x= 1/2
Solve for x: (2^{5x})/((2^{x+2))}=1
The solution is x= 1/2