What is the answer to 3^{x+5}=7^x ?

The answer to 3^{x+5}=7^x is x=(5ln(3))/(ln(7)-ln(3))

Solve for x: 3^{x+5}=7^x

The solution is x=(5ln(3))/(ln(7)-ln(3))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3^{x + 5} = 7^{x}

x = \frac{5 ln ( 3 )}{ln ( 7 ) - ln ( 3 )}

Decimal Notation

x = 6.48303 \dots

Solution steps

3^{x + 5} = 7^{x}

Apply exponent rules

(x + 5) ln (3) = x ln (7)

Solve

(x + 5) ln (3) = x ln (7) : x = \frac{5 ln ( 3 )}{ln ( 7 ) - ln ( 3 )}

x = \frac{5 ln ( 3 )}{ln ( 7 ) - ln ( 3 )}

3^{2 x - 1} = 7^{x + 1}

n, (1 + i)^{n} = 1.42

2 = 1 0^{x}

y, e^{y} = p^{3} + p

15000 = 750 0^{3 x}

What is the answer to 3^{x+5}=7^x ?
The answer to 3^{x+5}=7^x is x=(5ln(3))/(ln(7)-ln(3))
Solve for x: 3^{x+5}=7^x
The solution is x=(5ln(3))/(ln(7)-ln(3))