What is the answer to 7^{3p-5}= 1/((49^p)) ?

The answer to 7^{3p-5}= 1/((49^p)) is p=1

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7^{3p-5}= 1/((49^p))

7^{3 p - 5} = \frac{1}{( 4 9 ^{p} )}

p = 1

Solution steps

7^{3 p - 5} = \frac{1}{( 4 9 ^{p} )}

Apply exponent rules

3 p - 5 = - 2 p

Solve

3 p - 5 = - 2 p : p = 1

p = 1

Verify Solutions:

p = 1

True

The solution is

p = 1

3^{- x - 3} = 4^{- 3 x}

5^{x - 2} \cdot 3^{2 x - 3} = 135

5^{x} = 10

7^{x} + 7^{x - 1} = 8

9^{n} + 1 - 9^{n} = 72

What is the answer to 7^{3p-5}= 1/((49^p)) ?
The answer to 7^{3p-5}= 1/((49^p)) is p=1
Solve for p: 7^{3p-5}= 1/((49^p))
The solution is p=1