What is the answer to (1.03)^n=2 ?

The answer to (1.03)^n=2 is n=(ln(2))/(ln(1.03))

Solve for n: (1.03)^n=2

The solution is n=(ln(2))/(ln(1.03))

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(1.03)^{n} = 2

n = \frac{ln ( 2 )}{ln ( 1.03 )}

Decimal Notation

n = 23.44977 \dots

Solution steps

(1.03)^{n} = 2

Apply exponent rules

n ln (1.03) = ln (2)

Solve

n ln (1.03) = ln (2) : n = \frac{ln ( 2 )}{ln ( 1.03 )}

n = \frac{ln ( 2 )}{ln ( 1.03 )}

5^{2 x + 2} = 3^{5 x - 1}

\frac{( 8 \cdot 2 ^{n} + 2 \cdot 2 ^{n} )}{( - 2 ^{n + 1} + 4 \cdot 2 ^{n} )} = 5^{n}

e^{x} - 3 x = 0

4^{x} + 4^{x} + 2^{x} = 1

3^{x + 4} = 9^{x + 13}

What is the answer to (1.03)^n=2 ?
The answer to (1.03)^n=2 is n=(ln(2))/(ln(1.03))
Solve for n: (1.03)^n=2
The solution is n=(ln(2))/(ln(1.03))