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Popular >

solvefor x,2^x-1=3^y

Solution

solve for

x, 2^{x} - 1 = 3^{y}

Solution

x = \frac{ln ( 3 ^{y} + 1 )}{ln ( 2 )}

Solution steps

2^{x} - 1 = 3^{y}

Move

1

to the right side

2^{x} = 3^{y} + 1

Apply exponent rules

x ln (2) = ln (3^{y} + 1)

Solve

x ln (2) = ln (3^{y} + 1) : x = \frac{ln ( 3 ^{y} + 1 )}{ln ( 2 )}

x = \frac{ln ( 3 ^{y} + 1 )}{ln ( 2 )}

Popular Examples

e^{- x} = 0

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5^{x+2}*5^{5+2x}=125

5^{x + 2} \cdot 5^{5 + 2 x} = 125

3^{n + 3} = 9^{2 n}

2^{x - 8} = 4

Frequently Asked Questions (FAQ)

What is the answer to solvefor x,2^x-1=3^y ?
The answer to solvefor x,2^x-1=3^y is x=(ln(3^y+1))/(ln(2))