What is the answer to 5^{6t+7}=3^{2t} ?

The answer to 5^{6t+7}=3^{2t} is t=-(7ln(5))/(2(3ln(5)-ln(3)))

Solve for t: 5^{6t+7}=3^{2t}

The solution is t=-(7ln(5))/(2(3ln(5)-ln(3)))

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5^{6 t + 7} = 3^{2 t}

t = - \frac{7 ln ( 5 )}{2 ( 3 ln ( 5 ) - ln ( 3 ) )}

Decimal Notation

t = - 1.51031 \dots

Solution steps

5^{6 t + 7} = 3^{2 t}

Apply exponent rules

(6 t + 7) ln (5) = 2 t ln (3)

Solve

(6 t + 7) ln (5) = 2 t ln (3) : t = - \frac{7 ln ( 5 )}{2 ( 3 ln ( 5 ) - ln ( 3 ) )}

t = - \frac{7 ln ( 5 )}{2 ( 3 ln ( 5 ) - ln ( 3 ) )}

9^{2 x^{2} + 2 x} = 27

x 16 = 8^{- x} - 4

2^{- x} - 4 = 1 1^{6} x

\frac{2 ^{5 x}}{( 2 ^{x} )} = 3 2^{\frac{1}{5}}

n^{n} = 2

What is the answer to 5^{6t+7}=3^{2t} ?
The answer to 5^{6t+7}=3^{2t} is t=-(7ln(5))/(2(3ln(5)-ln(3)))
Solve for t: 5^{6t+7}=3^{2t}
The solution is t=-(7ln(5))/(2(3ln(5)-ln(3)))