What are the solutions to the equation 2x^2+2x-24=0 ?

The solutions to the equation 2x^2+2x-24=0 are x=3,x=-4

Find the zeros of 2x^2+2x-24=0

The zeros of 2x^2+2x-24=0 are x=3,x=-4

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2 x^{2} + 2 x - 24 = 0

x = 3, x = - 4

Solution steps

2 x^{2} + 2 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 2 ( - 24 )}{2 \cdot 2}

2^{2} - 4 \cdot 2 (- 24) = 14

x_{1, 2} = \frac{- 2 \pm 14}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 2 + 14}{2 \cdot 2}, x_{2} = \frac{- 2 - 14}{2 \cdot 2}

x = \frac{- 2 + 14}{2 \cdot 2} : 3

x = \frac{- 2 - 14}{2 \cdot 2} : - 4

The solutions to the quadratic equation are:

x = 3, x = - 4

\frac{1 - i}{9 + i}

2 p^{2} + 7 p + 6

- 8 p = 40

6 - \frac{8}{3}

\frac{- 75}{25}

What are the solutions to the equation 2x^2+2x-24=0 ?
The solutions to the equation 2x^2+2x-24=0 are x=3,x=-4
Find the zeros of 2x^2+2x-24=0
The zeros of 2x^2+2x-24=0 are x=3,x=-4