What is the answer to 4^{3x-1}=3(5^x) ?

The answer to 4^{3x-1}=3(5^x) is x=(ln(12))/(6ln(2)-ln(5))

Solve for x: 4^{3x-1}=3(5^x)

The solution is x=(ln(12))/(6ln(2)-ln(5))

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4^{3 x - 1} = 3 (5^{x})

x = \frac{ln ( 12 )}{6 ln ( 2 ) - ln ( 5 )}

Decimal Notation

x = 0.97468 \dots

Solution steps

4^{3 x - 1} = 3 (5^{x})

Apply exponent rules

(3 x - 1) ln (4) = ln (3) + x ln (5)

Solve

(3 x - 1) ln (4) = ln (3) + x ln (5) : x = \frac{ln ( 12 )}{6 ln ( 2 ) - ln ( 5 )}

x = \frac{ln ( 12 )}{6 ln ( 2 ) - ln ( 5 )}

3 = 2^{x}

256 = 2^{x}

(\frac{1}{3})^{13 - 3 x} = 9

2^{x} - 2^{\frac{x}{2} + 1} = 8

7^{x} = 5^{x}

What is the answer to 4^{3x-1}=3(5^x) ?
The answer to 4^{3x-1}=3(5^x) is x=(ln(12))/(6ln(2)-ln(5))
Solve for x: 4^{3x-1}=3(5^x)
The solution is x=(ln(12))/(6ln(2)-ln(5))