What is the answer to solvefor x,8^{2x}*3^{-1/2}*y=36 ?

The answer to solvefor x,8^{2x}*3^{-1/2}*y=36 is x=(ln((36*3^{1/2})/y))/(6ln(2))

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solvefor x,8^{2x}3^{-1/2}y=36

solve for

x, 8^{2 x} \cdot 3^{- \frac{1}{2}} \cdot y = 36

x = \frac{ln ( \frac{36 \cdot 3 ^{\frac{1}{2}}}{y} )}{6 ln ( 2 )}

Solution steps

8^{2 x} \cdot 3^{- \frac{1}{2}} y = 36

Divide both sides by

3^{- \frac{1}{2}} y

8^{2 x} = \frac{36}{3 ^{- \frac{1}{2}} y}

Simplify

\frac{36}{3 ^{- \frac{1}{2}} y} : \frac{36 \cdot 3 ^{\frac{1}{2}}}{y}

8^{2 x} = \frac{36 \cdot 3 ^{\frac{1}{2}}}{y}

Apply exponent rules

2 x ln (8) = ln (\frac{36 \cdot 3 ^{\frac{1}{2}}}{y})

Solve

2 x ln (8) = ln (\frac{36 \cdot 3 ^{\frac{1}{2}}}{y}) : x = \frac{ln ( \frac{36 \cdot 3 ^{\frac{1}{2}}}{y} )}{6 ln ( 2 )}

x = \frac{ln ( \frac{36 \cdot 3 ^{\frac{1}{2}}}{y} )}{6 ln ( 2 )}

5^{x} + 36 x - 97 = 0

(x + 2) e^{x - 1} - 1 = 0

2^{3^{8^{x}}} = 512

6^{x} = 1

2 x = 4 2^{x} - 1

What is the answer to solvefor x,8^{2x}*3^{-1/2}*y=36 ?
The answer to solvefor x,8^{2x}*3^{-1/2}*y=36 is x=(ln((36*3^{1/2})/y))/(6ln(2))