What is the answer to 3^{x^2-1}=134 ?

The answer to 3^{x^2-1}=134 is x=sqrt((ln(134))/(ln(3))+1),x=-sqrt((ln(134))/(ln(3))+1)

Solve for x: 3^{x^2-1}=134

The solution is x=sqrt((ln(134))/(ln(3))+1),x=-sqrt((ln(134))/(ln(3))+1)

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3^{x^{2} - 1} = 134

x = \frac{ln ( 134 )}{ln ( 3 )} + 1, x = - \frac{ln ( 134 )}{ln ( 3 )} + 1

Decimal Notation

x = 2.33628 \dots, x = - 2.33628 \dots

Solution steps

3^{x^{2} - 1} = 134

Apply exponent rules

(x^{2} - 1) ln (3) = ln (134)

Solve

(x^{2} - 1) ln (3) = ln (134) : x = \frac{ln ( 134 )}{ln ( 3 )} + 1, x = - \frac{ln ( 134 )}{ln ( 3 )} + 1

x = \frac{ln ( 134 )}{ln ( 3 )} + 1, x = - \frac{ln ( 134 )}{ln ( 3 )} + 1

x^{x} = 100

y, e^{3 x} + x^{2} \cdot y + e^{y} = 0

7^{x} + 7^{x + 1} - 7^{x + 2} + 7^{x - 1} = - 286

(\frac{1}{2})^{x} = 4

2^{3 x} = 8 + 2^{3 x - 1}

What is the answer to 3^{x^2-1}=134 ?
The answer to 3^{x^2-1}=134 is x=sqrt((ln(134))/(ln(3))+1),x=-sqrt((ln(134))/(ln(3))+1)
Solve for x: 3^{x^2-1}=134
The solution is x=sqrt((ln(134))/(ln(3))+1),x=-sqrt((ln(134))/(ln(3))+1)