What is the answer to 17^{-3x}=9^{x+9} ?

The answer to 17^{-3x}=9^{x+9} is x=(18ln(3))/(-3ln(17)-2ln(3))

Solve for x: 17^{-3x}=9^{x+9}

The solution is x=(18ln(3))/(-3ln(17)-2ln(3))

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1 7^{- 3 x} = 9^{x + 9}

x = \frac{18 ln ( 3 )}{- 3 ln ( 17 ) - 2 ln ( 3 )}

Decimal Notation

x = - 1.84867 \dots

Solution steps

1 7^{- 3 x} = 9^{x + 9}

Apply exponent rules

- 3 x ln (17) = (x + 9) ln (9)

Solve

- 3 x ln (17) = (x + 9) ln (9) : x = \frac{18 ln ( 3 )}{- 3 ln ( 17 ) - 2 ln ( 3 )}

x = \frac{18 ln ( 3 )}{- 3 ln ( 17 ) - 2 ln ( 3 )}

6^{l o g_{5} (x^{2} - 8 x + 24)} = 3^{l o g_{5} (36)}

8^{x} = 64

\frac{( 2 ^{1 - x} - 2 ^{x} + 1 )}{( 2 ^{x} - 1 )} = 0

2^{2 x + 2} = 4^{2 x - 1}

9^{n + 1} - 2 \cdot 9^{n} = 7

What is the answer to 17^{-3x}=9^{x+9} ?
The answer to 17^{-3x}=9^{x+9} is x=(18ln(3))/(-3ln(17)-2ln(3))
Solve for x: 17^{-3x}=9^{x+9}
The solution is x=(18ln(3))/(-3ln(17)-2ln(3))